iuh

docs/paper/sections/q2.tex

@@ -105,22 +105,11 @@ $1.005^\circ$ & 750.115391 & 249.884609\\
 
 \begin{figure}[htbp]
 \centering
-\begin{tikzpicture}[x=0.006cm,y=0.006cm,font=\small,>=Stealth]
- \fill[inkblue!8] (0,0)--(1499.77,-26.18) arc[start angle=-1,end angle=1,radius=1500]--cycle;
- \draw[inkblue!45] (750.114,0) circle (750.114);
- \filldraw[fill=inkblue!12,draw=inkblue,thick] (750.114,0) circle (249.885);
- \draw[thick] (0,0)--(1499.77,26.18);
- \draw[thick] (0,0)--(1499.77,-26.18);
- \draw[->,dashed] (0,0)--(1650,0) node[right] {$u(\theta)$};
- \fill (0,0) circle (8) node[below left] {$s$};
- \fill[inkblue] (750.114,0) circle (8) node[below] {$c$};
- \draw[->,inkblue] (1010,345)--(890,155);
- \node[anchor=west,inkblue] at (990,390) {保证接收候选盘};
- \node at (750,-850) {圆域先验 $\Omega$ 可进一步收紧候选集};
- \node[anchor=east] at (1570,-125) {首次截断角域 $S$};
- \node[inkblue!70] at (750,830) {截断角域的最小包围圆};
-\end{tikzpicture}
-\caption{第二点解析候选区域的几何关系，采用 $1^\circ$ 半角、同一坐标比例绘制。}
+\includegraphics[width=0.70\linewidth]{geo-q2-guaranteed-reception-disk.png}
+\caption{第二点解析候选区域。左图为首次截断角域 $S$、
+其最小包围圆 $\B(c,a)$ 与保证接收的候选盘 $\B(c,1000-a)$；
+右图为半径分解，$a=1500/(2\cos\delta)$。取 $\delta=1^\circ$ 时
+$a\approx750.114$ m、$1000-a\approx249.886$ m，与表~\ref{tab:safeanalytic} 一致。}
 \label{fig:q2disk}
 \end{figure}